What is the value of $\alpha +\beta$?

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If $U=f(P,V,T)$ be the internal energy of a gas that obeys the ideal gas law $PV=nRT$, ($n$ and $R$ constants) and$(\frac{∂U}{∂T})_v+(\frac{∂U}{∂P})_v=α(\frac{∂U}{∂T})+β(\frac{∂U}{∂P})$then α+β equals

(A)$2+\frac{v}{nR}+\frac{nR}{v}$

(B)$1+\frac{v}{nR}$

(C)$1+\frac{n}{Rv}$

(D) 1

Let us take $U\equiv PV-nRT$,then $(\frac{∂U}{∂T})_v+(\frac{∂U}{∂P})_v=α(\frac{∂U}{∂T})+β(\frac{∂U}{∂P})\implies -nR+V=-\alpha nR +\beta V$

on comparing coefficient of both sides we get $\alpha=1$ and $\beta =1$.So,$\alpha +\beta =2$

But it does not matches with none of the option.

Where i'm commiting mistake??