What is the value of $\sin(53^\circ)$ equal to in cos? (Unit Circle)

Question

I tried this and I only got $\sin( 53^\circ)= \sin( 127^\circ).$ How do I find the equal value in cosine or tangent? Please help me out. Thank you!

Answer 1

Use:

$sin(90^\circ + \theta )= cos(\theta)$

$sin(90^\circ - \theta )= cos(\theta)$.

So:

$sin(53^\circ)=sin(90^\circ - 37^\circ )= cos(37^\circ)$.

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Answer 2

We can use the identity $\sin x^\circ = \cos {(90^\circ-x^\circ)}$ so $\sin{53^\circ}=\sin{127^\circ}=\cos{(127^\circ-90^\circ)}=\cos{37^\circ}.$

I can't think of an simple way to express it in tangent.