What is the value of $ \sum_{n=1}^{9999} \big [ \dfrac {1} {n^{\frac{1}{4}}}\big ]$ where $[\cdot] $ is the greatest integer function.
I do not seem to possess any clue about this problem. Any hints will be deeply appreciated please.
Thank you!
What is the value of $ \sum_{n=1}^{9999} \big [ \dfrac {1} {n^{\frac{1}{4}}}\big ]$ where $[\cdot] $ is the greatest integer function.
I do not seem to possess any clue about this problem. Any hints will be deeply appreciated please.
Thank you!
Mh, what about
$$1+0+0+0+0+0+0+0+0+0+0+0+0+0+0+0+0+0+\cdots 0\ ?$$
If the question is in fact
$$\sum_{1}^{9999}\frac1{\lfloor \sqrt[4]n\rfloor},$$
consider that there are
$15$ terms (from $1$ to $15$) equal to $1$,
$65$ terms (from $16$ to $80$) equal to $\dfrac12$,
$175$ terms (from $81$ to $255$) equal to $\dfrac13$,
$\cdots$
$3439$ terms (from $6561$ to $9999$) equal to $\dfrac19$.