What is the value of:
$$\prod_1^\infty \frac{p_i^2}{p_i^2 -1 }$$ Where $$p_i$$ are the prime numbers: 2, 3, ...
What is the value of:
$$\prod_1^\infty \frac{p_i^2}{p_i^2 -1 }$$ Where $$p_i$$ are the prime numbers: 2, 3, ...
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The value is $\pi^2/6$.
Here are two steps to take (made edit to the equation):
$\frac{p^2}{p^2-1} = \frac{1}{1 - p^{-2}}$
$\frac{1}{1 - p^{-2}} = \sum_{j \ge 0} p^{-2j}$.
Now, taking the product of all these sums you get $\sum_{n \ge 1} n^{-2}$. For the last you likely know the value; if not I recalled it above.