I have the relation:
$$T = \{(i,j) \in \mathbb{N}^2 \mid i-10=j\}$$
And I need to find the relation $T^+$ (the transitive closure relation)
which I dont really understand
PS. need help formatting
On
The transitive closure of T, a binary relation for A, is the
intersection of all transitive relations containing T.
First note that A×A is a transitive relation for A that
contains every relation for A including T.
Thus the intersection is not empty. In addition any
intersection of transitive relations for A is transitive.
Hence the definition is well defined, being the smallest transitive
relation contaning T.
For a point by point description, it is the set of all pairs
(a,b) for which there is a sequence x1,.. x_n (possibility zero
long) with aTx1, x1Tx2,.. x_nTb.
To prove this is the transitive closure, first show it is
transitive and contains T. Next show that every transitive
relation containing T, must contain all of the above described (a,b).
The transitive closure of a relation $T$ is the smallest relation $T'$ that:
$(10,0)\in T$, and $(20,10)\in T$, so we'd expect by transitivity that $(20,0)\in T$, but this isn't true. We'd need to add $(20,0)$ to $T'$ for this to have any hope of being transitive, but this alone won't be enough.
I'd suggest to repeat the above process a few times, and see if there's some pattern to the stuff you need to add. By this, I mean that if you also need to add $(21,1)$ (which you will), does this means that $T'$ just has to be everything of the form $(n+10,n)$ and $(n+20,n)$? Is this enough to make it transitive? Or you will you have to add more?
If you're struggling, a stronger hint is below:
Furthermore, the solution is below, but I'd recommend you try to figure it out yourself still.