2026-03-28 08:10:33.1774685433
what is wrong with following right triangle's hypotenuse's square reasoning
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1
Since you talk about hypotenuse, it means that the diagonals of the quadrilateral are perpendicular. Using $$c^2=a^2+b^2$$ and $$c^2=2ab$$ you get $$a^2+b^2-2ab=0$$ or $$(a-b)^2=0$$This is valid for $a=b$