Why $\sqrt{-1} = (-1)^{1/2} = (-1)^{2 \times {1/4}} = (-1^2)^{1/4} = 1^{1/4} = 1$ is not true?
2026-03-28 14:55:13.1774709713
What is wrong with $\sqrt{-1} = (-1)^{1/2} = (-1)^{2 \times {1/4}} = (-1^2)^{1/4} = 1^{1/4} = 1$?
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You use the fact that $(x^a)^b = x^{ab}$, a fact that is only true for $x>0$. In fact, for negative values of $x$, the term $$x^{a}$$
is only really properly defined for integer values of $a$, so even the expression $\sqrt{-1}$ is not well defined. Sure, you could say that $i=\sqrt{-1}$, but you could also say that $\sqrt{-1} = -i$, since both $i$ and $-i$ solve the equation $$x^2+1=0.$$