The teacher said , the work can be done alone or in a group . So students can make group to do the work . $\frac{2}{3}$th portion of male students and $\frac{3}{5}$th portion of female students done the work in group . So what portion of work is done alone by students of a class ?
My trying :
I have understood that this problem can be solved using vann diagram concept . But I cant understand how the concept of vann diagram should be applied here ?
Let $b$ the proportion of boys in the class, so $1-b$ i the proportion of girls (this is where Venn diagram helps).
We have that:
$\frac{2}{3}b + \frac{3}{5}(1-b)$ is the opposite of the proportion you are looking for. Simplifying a bit:
$\frac{1}{15}b + \frac{9}{15}$
The proportion of students, not working in group is:
$1 - (\frac{1}{15}b + \frac{9}{15}) = \frac{6}{15} - \frac{1}{15}b$
Doing some further assumption like the proportion of boys and girls is the same, so $b=\frac{1}{2}$. We can say the the proportion of students working in group is:
$\frac{1}{15}\frac{1}{2} + \frac{9}{15} = \frac{19}{30}$
And of course the proportion of students not working in group, supposing there is the same number of boys and girls, would be $1-\frac{19}{30} = \frac{11}{30}$