In a solution to one of my assignment is given that:
$$4^{log_{16} n} = n^{log_{16} 4} = n^{\frac12}$$
I understand the 2nd part, that's simple, but how was the first part achieved?
In a solution to one of my assignment is given that:
$$4^{log_{16} n} = n^{log_{16} 4} = n^{\frac12}$$
I understand the 2nd part, that's simple, but how was the first part achieved?
Let $$y=4^{\log_{16}x}$$ $$\log_{16}y=\log_{16}(x^{\log_{16}4})$$ $$\log_{16}y=\log_{16}(x^{1/2})$$ $$y=x^{1/2}$$