Second National Bank offers an account that earns $4.91\%$ per year, compounded continuously. If a person invests $\$20,000$ in this account, what will be the value of the account at the end of $12$ years? (Round your answer to the nearest cent.)
When I did this problem I used the formula $20,000(1+0.0491)^{12}$ and got $\$35549.43$ but it was marked incorrect so I was wondering what I was doing wrong?
$C*e^{rt}$
$20,000(e^{.0491*12})= 36,050.92$