What $x$ satisfies $3^{4x}\cdot 9^6 = 81^8$?
I reckon it is possible to rearrange bases $3$ and $9$ to $81$, but I don't know how. Which rules apply here?
2026-04-28 12:19:16.1777378756
What $x$ satisfies $3^{4x}\cdot 9^6 = 81^8$?
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$$3^{4x}\cdot 3^{12}=3^{32}$$
Thus
$$4x+12=32$$
$$x=5$$