Let $G$ be a topological group. If $H$ is a closed subgroup such that the identity component $H^0$ of $H$ is only the identity element i.e $H^0=\{e\}$. is it true that $H$ is a discrete subgroup of $G$?
2026-03-28 13:59:57.1774706397
When the identity component is only one point
65 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
It's not true in general. There exist topological groups $G$ homeomorphic to the Cantor set, for example the inverse limit of the sequence of surjective homomorphisms of finite cyclic groups $$\cdots \to \mathbb{Z} / 2^n \mathbb{Z} \to \mathbb{Z} / 2^{n-1} \mathbb{Z} \to \cdots \to \mathbb{Z} / 2^2 \mathbb{Z} \to \mathbb{Z} / 2\mathbb{Z} $$ Then take $H=G$. The components are single points, but $H=G$ is not discrete.