Where does $\;f(z)=\displaystyle \frac{1}{z} +e^{2i \gamma}z\;$ maps the unit disk $|z|<1$ in $w$- plane? given that $0 \leq \gamma \leq 2\pi$

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Where does mapping $\;f(z)=\displaystyle \frac{1}{z} +e^{2i \gamma}z\;$ maps the unit disk $|z|<1$ in $w$- plane? given that $0 \leq \gamma < 2\pi$

Solution i tried - Given mapping is $$\;f(z)=\displaystyle \frac{1}{z} +e^{2i \gamma}z\;$$

we can write it as $$f(e^{i\theta})=e^{-i\theta}+e^{2i\gamma}e^{i\theta}$$

$$f(e^{i\theta})=\displaystyle e^{i\gamma}\left(e^{-i \theta}e^{- i\gamma}-e^{i \theta}e^{ \gamma}\right)$$

$$f(e^{i\theta})=\displaystyle2 e^{i\gamma}\cos(\theta+\gamma)$$

but after this i am not getting how to check its image in $w-$ plane ,because of that $\gamma$ , please help.

Thank you