Where does the $2 \pi$ come from in the Fourier Transform Equation?

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So I was working through the Fourier transform equations that arise. I was wondering where the radical outside the integral originated from?

$\hat{f}(k) = \sqrt{\frac{|b|}{(2 \pi)^{1-a}}} \int_{-\infty}^{\infty} dx \, f(x) \, e^{i b k x}$

and

$f(x) = \sqrt{\frac{|b|}{(2 \pi)^{1+a}}} \int_{-\infty}^{\infty} dk \, \hat{f}(k) \, e^{-i b k x}$

I was wondering where that radical originated. I always just found these equations simply stated and could not figure out where they came from and how that term came out of the integral?

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Just so that you have the identity $\|f\|_2=\|\hat{f}\|_2$, called Plancherel's theorem.