I am following this slide on FFT. On the last page, it says:
I would like to ask where $a = A(2)$ comes from. Thanks.
I am following this slide on FFT. On the last page, it says:
I would like to ask where $a = A(2)$ comes from. Thanks.
Copyright © 2021 JogjaFile Inc.

In base two, a number $b = b_{n-1}\dots b_0$ stands for $b = \sum_{i=0}^{n-1} b_i 2^i$.
Defining the polynomial $B(X) =\sum_{i=0}^{n-1} b_i X^i$, you have $b = B(2)$.
Note : in base $\beta$, the number $b = b_{n-1}\dots b_0$ is $B(\beta)$.