This question seems a bit stupid but I am really confused: Let $f$ be a function and $g(z):=f(z)-f(2z)$.
What is $g(-1/z)$? Is it $f(-1/z)-f(-2/z)$ or $f(z)-f(-1/(2z))$?
Thank you!
This question seems a bit stupid but I am really confused: Let $f$ be a function and $g(z):=f(z)-f(2z)$.
What is $g(-1/z)$? Is it $f(-1/z)-f(-2/z)$ or $f(z)-f(-1/(2z))$?
Thank you!
You blindly substitute the occurences of $z$ in the $g$ function WITH parenthesis around $z$ when the occurence is not trivial and then do some algebra to possibly simplify it. $$ g(-1/z) = f(-1/z) - f(2 (-1/z)) = f(-1/z) - f(-2/z) $$