This is likely a silly question, but I cannot find an answer on the internet. I used Sage-math to find the structure of a group presented as:
$$\langle x,y; xy=1 \rangle$$
It returned C0: which group is it?
EDIT Here is the code I used
sage: G.<x,y,z,t>=FreeGroup()
sage: H=G.quotient([x*y,x*z,x*t])
sage: H.structure_description()
'C0'
I'm not sure what $\;C_0\;$ means, but that group of yours is $\;\Bbb Z\;$ , the infinite cyclic group (though you wrote it multiplicatively). Observe that from the unique relation given, we get
$$xy=1\implies y=x^{-1}\implies K:=\langle x, y\;|\; xy=1\rangle=\langle x,x^{-1}\rangle =\langle x\rangle\cong\Bbb Z$$