Page 29 of Source 1: Denote the complex conjugate by * : $\mathbf{u \cdot v} = \sum_{1 \le i \le n} u_i^*v_i = (\mathbf{v \cdot u})^*$
Page 1 of Source 2: $\mathbf{u \cdot v} = \mathbf{u}^T\mathbf{ \bar{v} }$.
Page 1 of Source 3: Denote $\mathbf{u^*} = \mathbf{\bar{u}^T} $. Then $ \mathbf{ <u,v> = u*v = \bar{u}^Tv } $.
Would someone please explain and elucidate all these differences? Which is right? I'm confused. I believe that $u \cdot v = <u, v>$, if $< >$ is considered as the $\cdot$?
In view of the answer below, which is the most convenient and powerful that I should remember?
Source 1. and 3. are identical. It depends on the convention: there is not really a big difference, just in one case it is linear in the first entry and antilinear ($(u, \alpha v)=\bar\alpha (u,v)$) in the second entry (Source 2) and in the other convention, it is antilinear in the first and linear in the second entry (Source 1 and 3). I believe that more common is the convention from source 1 & 3.