I have this Boolean expression:
$y = ab + (a + b)' + (a'b)'$
$ = ab + a'b' + a + b'$
$ = a(1 + b) + b'(1 + a')$
$ = a + b'$
Is $(a + b')$ the simplest answer or:
$a + b' = (a'b)'$ the simplest?
Thank you for help.
I have this Boolean expression:
$y = ab + (a + b)' + (a'b)'$
$ = ab + a'b' + a + b'$
$ = a(1 + b) + b'(1 + a')$
$ = a + b'$
Is $(a + b')$ the simplest answer or:
$a + b' = (a'b)'$ the simplest?
Thank you for help.
Generally, an expression is only considered "simplified" if each "not" (that is, each ') is applied directly to a variable. I would say that $(a'b)'$ is not simplified because the outer ' is applied to $(a'b)$ as opposed to $a$ or $b$.
So, $a + b'$ is certainly a simpler form than $(a'b)'$.