Which of these are constructible numbers?
$$-\frac35\quad,\quad27^\frac16+2i\quad,\quad2^\frac13\quad,\quad e^{\frac{\pi i}{10}}$$
Please tell me how you came to the answer too. Thanks!
Which of these are constructible numbers?
$$-\frac35\quad,\quad27^\frac16+2i\quad,\quad2^\frac13\quad,\quad e^{\frac{\pi i}{10}}$$
Please tell me how you came to the answer too. Thanks!
Ok, so you already know what numbers are constructible and what not. Now, why? Be sure to complete the following arguments, and remember: a number is constructible iff it belongs to a tower of field extension each of which is of degree two, i.e. $\;z\in\Bbb C\;$ is constructible iff $\;z\in K\;,\;\;K\;$ a subfield of $\;\Bbb C\;$ , and such that
$$\Bbb Q=K_0\subset K_1\subset K_2\subset\ldots\subset K_n =K\;,\;\text{and}\;\;[K_i:K_{i-1}]=2\;\;\;\forall\; i=1,2,...,n\;,\;\;or\;\; K=\Bbb Q$$
So:
$$\begin{align*}&-\frac35\in\Bbb Q\implies\color{red}{-\frac35\;\;\text{constructible}}\\{}\\ &\begin{cases}27^{1/6}=\sqrt3\in\Bbb Q{\sqrt3}\;\;\text{and}\;\;[Q(\sqrt3:\Bbb Q]=2\\{}\\2i\in\Bbb Q(i)\;\;\text{and}\;\;[\Bbb Q(i):\Bbb Q]=2\end{cases}\implies\color{red}{\sqrt[6]{27}+2i\in\Bbb Q(\sqrt3,i)\;\;\text{constructible}}\\{}\\ &e^{\pi i/10}=e^{2\pi i/20}\;\;\text{and}\;\;\varphi(20)=8=2^3\implies\;\color{red}{e^{\pi i/10}\;\;\text{constructible, or follows also from:}}\\{}\\&\text{the fact that the minimal polynomial over the rationals of}\;\;e^{\pi i/10}\;\;\text{is}\;\;x^8-x^6+x^4-x^2+1\end{align*}$$
This last result follows from factoring $\;x^{10}+1=\left(x^2\right)^5+1\;$ .
Finally
$$\sqrt[3]2\in\Bbb Q(\sqrt[3]2)\;,\;\;\text{and}\;\;[\Bbb Q(\sqrt[3]2:\Bbb Q]=3\implies \color{green}{\sqrt[3]2\;\;\text{isn't constructible}}$$