Vertex of a parabola is on y axis. and the point (4,7) is on this parabola.
which one of these points definitly on the parabola : (-4,7),(2,7),(0,11),(-2,7) or (0,-5)
Let $(0,b)$ be the vertex point. so the equation should be $y=ax^2+b$ or $x=c(y-b)^2$ so There are 4 possible parabolas
$16a+b=7$
$4=c(7-b)^2$
$c=\frac{1}{64a^2}$
shouldnt it give us more information?
Although the parabola is not completely described, you do have enough information to check whether one of the listed points is on the parabola. Specifically, $(-4,7)$ must be on the parabola because its center is on the y-axis.
Regarding the other points: $(2,7)$ cannot be on the parabola because it conflicts with $(4,7)$ (and by extension neither can $(-2,7)$). Either $(0,11)$ or $(0,-5)$ might be the vertices but you can't say for sure.