Why are these two solutions not included in the solution of $\tan 2x = 2$?

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The question asks to solve, in the interval $-180° \leq x < 180°$, the equation:

$$\sin x (\cos x + \csc x) = 2 \cos^2 (x)$$

This equation simplifies to

$$\tan 2x = 2$$

According to this, $2x$ (with a domain multiplied by $2$ to become $-360° \leq x < 360°$) must be the following: $63.43°, 243.43°, -116.57°,$ and $-296.57°$. And therefore, after dividing by $2$, x must be: $31.7°, 121.7°, -58.3°, -148.3°$

However, the answer excludes these two: $121.7°$ and $-148.3°$

I don't understand why.