Why borel set $\mathcal{B}_\mathbb{C} = \mathcal{B}_{\mathbb{R}^2}$
2026-03-25 23:16:06.1774480566
Why borel set over complex is the same as real plane?
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$(x,y) \to x+iy$ is a homeomorphism from $\mathbb R^{2}$ onto $\mathbb C$. Any homeomorphism preserves open sets, hence also Borel sets.