I'm a math teacher, but this aspect of stats is not my strong point. I've asked several other teachers as to why, and their responses was just "don't do it" the why was not very compelling, so I come here. $H_\text{null}$ = $m$ and $n$ are independent. $H_\text{alt}$ = $m$ and $n$ are NOT independent.
If condition $p$ is met, we accept the null hypothesis.
If condition $p$ is not met, we reject the null hypothesis.
Isn't the rejection of the null hypothesis logically equivalent to the alt hypothesis? Isn't the negation of ($m$ and $n$ are independent) = ($m$ and $n$ are Not independent)?
Thank you kindly for your response.
I don't think the answer to this question is specific to the chi-squared distribution or the chi-squared test. In general, the alternative hypothesis is not associated with a specific distribution of the test statistic.
We reject the null hypothesis if the probability that we would observe values of the test statistic as extreme or more extreme than the value of the test statistic that we observed is less than or equal to $\alpha$.
This means that if the null hypothesis is actually true, we will reject it with probability $\alpha$. That's what we're picking when we pick $\alpha$.
The distribution in question for the test statistic is the Chi-squared distribution. This distribution is well-defined because there's really only one way for standard normal random variables to be independent of each other.
However, if the standard normal random variables are not independent, then how would we construct a distribution for the test statistic in principle?