I don't really understand why to show $A\subseteq B$, all we need to show is that $\exists x \in A$ and $x \in B$?
Doesn't this notation mean that there is a specific element of A inside B, not arbitrary element of A is within B? Hence, you should say $\forall x \in A$, $x \in B$?
I'm not sure where you've seen that $\exists x \in A (x \in B)$ is equivalent to $A \subseteq B$, but that's false. For $A$ to be a subset of $B$ means that for every element $x$ of $A$, the element $x$ is also an element of $B$, i.e. $\forall x (x \in A \to x \in B)$.
In practice, we show that $A \subseteq B$ by taking a generic element of $A$ and showing it's also an element of $B$. This is possible because the sets $A$ and $B$ are usually given by certain defining formulas. For example, $A$ might be the set $\{m \in \mathbb{N} | \exists n \in \mathbb{N}(m=2n \wedge n \geq 10) \}$, i.e. the set of even numbers greater than or equal to $20$. If we want to show $A \subseteq \{20, 21, 22, ...\}$ we simply take an arbitrary $x \in A$ and show it satisfies the defining condition of $\{20,21,22,...\}$.