Why does the continuity of Lyapunov function matter?

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Why does the continuity of Lyapunov function matter?

Is there any example where discontinuity of $V$ is problematic even if it does not change the sign but it is strictly decreasing and yet not stable?


From wikipedia:

A Lyapunov function for an autonomous dynamical system

\begin{cases}g:\mathbb {R} ^{n}\to \mathbb {R} ^{n}\\{\dot {y}}=g(y)\end{cases}

an equilibrium point at $y=0$ is a scalar function

$$V: \mathbb{R}^n\to \mathbb{R}$$

that is continuous, has continuous derivatives, is locally positive-definite, and for which $-\nabla V.g$ is also locally positive definite. The condition that $-\nabla V.g$ is locally positive definite is sometimes stated as $\nabla V.g$ is locally negative definite.