Why does the hypotenuse of half the triangle (formed from a circle) ≈ pi * r?

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Just a while ago, while feeling bored, I took a pen and pencil, and started doing some math. After a while of doing something I found out that the hypotenuse of half the triangle (formed from a circle) ≈ pi * r Here's how I got to that:

  1. Convert the circle into a triangle
  2. Now, the radius is the height of the triangle, and the circumference is the base of the triangle
  3. Next we replace the radius with r (for simplicity), and replace the circumference with its formula (2 pi * r)
  4. Next we divide the triangle in half (making identical 2 triangles)
  5. Now the base of the triangle is half (pi * r), but the height is the same (r)
  6. Now we try to calculate the hypotenuse --
    h = sqrt( (r)^2 + (pi * r)^2 )

    Note: sqrt means square root

  7. Now we add in the values and calculate

For some reason, the hypotenuse ≈ pi * height For example: radius(h) = 3 cm sqrt( (r)^2 + (pi * r)^2 )
= sqrt( (3)^2 + (3.14 * 3)^2 )
= sqrt( 9 + (9.42)^2 )
= sqrt( 9 + 88.7364 )
= sqrt( 97.7364 )
= 9.88617216116

Which approximately equals: pi * r = 3.14 * 3 = 9.42

Please tell me if I'm missing something super obvious.

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You appear to be forming an isosceles triangle by "unrolling" a circle a distance equal to its circumference to form the base of a triangle with height equaling the radius.

Then the length of the two congruent sides equals $\sqrt{r^2+\pi^2r^2}=r\sqrt{1+\pi^2}$.

Can you see now why this "approximately" equals $\pi r$?