Why does the Kronecker Delta get rid of the summation?

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I am working with spherical harmonics and the radial equation (part of Laplace's equation in spherical co-ords). The coefficients and equations with I am working with aren't important to my question.

I am using the orthogonality relation for spherical harmonics:

$<Y_{kn},Y_{lm}> = \int^{2\pi}_0\int^{\pi}_0 Y^*_{lm} Y_{kn} sin(\theta) d\theta d\phi = \delta_{kl} \delta_{mn}$

In the problem below:

$<Y_{kn},f> = \sum\limits_{l=0}^\infty\sum\limits_{m=-l}^\infty (A_{lm}a^l)<Y_{kn},Y_{lm}>$

We can use the orthogonality relation to get:

$<Y_{kn},f> = \sum\limits_{l=0}^\infty\sum\limits_{m=-l}^\infty (A_{lm}a^l)\delta_{kl} \delta_{mn}$

Which simplifies to:

$<Y_{kn},f> = A_{kn}a^k$

Why do the Kronecker deltas "get rid off" the summation signs and why have we relabelled the coefficients on the right hand side?

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Because

$$\delta_{kl}=\begin{cases}0&,\;\;k\neq l\\{}\\1&,\;\;k=l\end{cases}$$

so in that sum all equals zero except when $\;l=k\;,\;m=n\;$