I am using the following algorithm to render the Mandelbrot set and the exterior:
• for each test point, calculate $c$
• initialise $z_{0}=(0+0i)$
• also initialise the gradient $dz_{0}=(0+0i)$
• iterate the following for the maximum allowed iterations
– calculate next $z$ using $z\mapsto z^{2}+c$
– calculate next gradient $dz$ using $dz\mapsto2\cdot z\cdot dz+1$
– break out of iteration loop if $|z|>4$ escape condition met
• calculate distance estimate as $d=\left(|z|\cdot\log|z|\right)/|dz|$
• colour the pixel based on distance estimate, eg $255\times\tanh(d\times \text{resolution}/\text{size})$ using a grey scale, 0-black, 255-white
The following shows a square viewport that has a bottom left at $(-0.7416363282638+0.1804439806419i)$, and a width of $0.008304417869$.
It seems to me that the red-circled mini-Mandelbrot shapes are part of the fully-connected Mandelbrot set and should be coloured black.
Question: Why are they white?
Thoughts: Even with non-zoomed views, I have seem some of the bulbs of The Mandelbrot coloured white.

I think the formula you are using is valid only for points in the exterior. There is a more complicated formula for interior points, that you can find on this Wikipedia page.
Note that the formula refers to the period of the point under consideration. Also note that each mini-brot that you see corresponds to some particular period and each point in that mini-brot corresponds to a critical orbit whose period is a multiple of that common period.