Let $X=[0,1]^2$ and $(0,a)\sim(1,a), \ (b,0)\sim(b,1) \Rightarrow X/\sim \ \cong (S^1)^2$. I don't see why $X/\sim$ is torus, can someone explain?
2026-04-02 21:00:37.1775163637
Why does this equivalence relation give a torus?
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Convince yourself that it produces the following gluing indicated on the boundaries. The pictures show the gluing to give a torus.