Why does this exponential identity hold? $3\cdot 2^{2n+2} - 3\cdot2^{2n} = 3\cdot2^{2n}$

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Can someone explain how this is valid?

$$3\cdot 2^{2n+2} - 3\cdot2^{2n} = 3\cdot2^{2n}$$

Thanks so much!

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Taking out a common factor allows you to rewrite the expression as follows: $$3\cdot2^{2n+2}-3\cdot2^{2n}=3\cdot2^{2n}\cdot(2^2-1)=3^2\cdot2^{2n}.$$ This shows that your formula is not valid; it's off by a factor $3$.