As the title states, I was wondering why
$2-2\cos(x) = 4\sin^2(\frac{x}{2})$
holds true?
Use the formulas $\cos (A+B)=\cos A\cos B-\sin A \sin B$ and $\cos^{2}C+\sin ^{2}C=1$. [ Take $A=B=\frac t 2$].
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Use the formulas $\cos (A+B)=\cos A\cos B-\sin A \sin B$ and $\cos^{2}C+\sin ^{2}C=1$. [ Take $A=B=\frac t 2$].