Why is -2 an answer for $\frac{|x+3|+x}{x+2} > 1$?

Question

In the inequality $\frac{|x+3|+x}{x+2} > 1$, by doing sign chart method the answer I am getting is $x \in (−5,−2)\cup(−1,\infty)$

But the graph in Desmos shows that it should be $x \in (−5,−2]\cup(−1,\infty)$ with solid line on -2 but dots on -5 and -1

Wolfram appears to be on my side though, as seen in the interval notation at the bottom

Am i reading it wrong or is Desmos wrong?

Answer 1

$-2$ is not a solution. You cannot compute the left side at $x=-2$ because of the division by $0$.