Let $A$ be a commutative ring, $I \subset A$ a finitely generated ideal. Define $\hat{A} := \varprojlim A/I^n$.
What is the best way to proof that $A/I^nA \cong \hat{A}/I^n \hat{A}$ for all $n$?
2026-04-23 20:01:37.1776974497
Why is $A/I^n A \cong \hat{A}/I^n \hat{A}$?
37 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail AtRelated Questions in RING-THEORY
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