I have this equation:
$x^2+(x-7)^2=13^2$
Why can't squaring the whole equation be used to solve it?
$\sqrt{x^2+(x-7)^2=13^2}\equiv x+x-7=13$
My question is merely asking when square cannot be used to solve an equation.
I have this equation:
$x^2+(x-7)^2=13^2$
Why can't squaring the whole equation be used to solve it?
$\sqrt{x^2+(x-7)^2=13^2}\equiv x+x-7=13$
My question is merely asking when square cannot be used to solve an equation.
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Following your approach, we would get $x=10$.
But neither $10^2+3^2=13^2$, nor $\sqrt{10^2+3^2}=13$.
You can indeed "square root" the equation (with some care for the signs), but you may not "square root" a sum.
Indeed, $(a+b)^2=a^2+2ab+b^2\ne a^2+b^2$ so that $a+b\ne\sqrt{a^2+b^2}$.