Let $M$ be a smooth manifold and $E\to M$ a vector bundle over $M$ and $\nabla:\Gamma(E) \to \Gamma(T^*M\otimes E)$ a connection on $E$.
The curvature $R$ of the connection is defined as $$R: \mathfrak{X}(M) \times \mathfrak{X}(M) \times \Gamma(E) \to \Gamma(E)$$ with $$R(X,Y)s=\nabla_X\nabla_Y s - \nabla_Y\nabla_Xs - \nabla_{[X,Y]}s.$$
Now for any $p \in M$ why is $$R_p:T_pM\times T_pM \to \operatorname{Hom}(E_p,E_p)?$$
$R(X,Y)s$ evaluated at $p \in M$ should give $$(R(X,Y)s)(p)=R_p(X_p,Y_p)s(p)$$ where $X_p,Y_p \in T_pM$ and $s(p) \in E_p$ so how is this a map from $T_pM \times T_pM$ to $\operatorname{Hom}(E_p,E_p)$?