A knot $K$ is $p$-colorable if and only if the det($K$) is divisible by $p$.
So why is the |det($5_2$)| $=7$, and not a multiple of 5, especially when there are only 5 arcs in the knot?
A knot $K$ is $p$-colorable if and only if the det($K$) is divisible by $p$.
So why is the |det($5_2$)| $=7$, and not a multiple of 5, especially when there are only 5 arcs in the knot?
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