Let X be a topological space. Let A,B ⊂ X and A ⊂ B.
Why is $ \bar{A} \subset \bar{B}$ true?
$\bar{A}$ is the smallest closed set containing $A$. Now $\bar{B}$ is closed by definition and contains $B$, hence $A$, and the statement follows.
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$\bar{A}$ is the smallest closed set containing $A$. Now $\bar{B}$ is closed by definition and contains $B$, hence $A$, and the statement follows.