Why is the Laplacian of $|f(x+iy)|^2$ equal to $4|′()|^2$?

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In a question about harmonic and holomorphic functions in complex analysis, I was trying to expand $|f(x+iy)|^2 = 0$.

I did this by considering $f(z) = u(z) + iv(z)$ and applying the Laplacian operator on $u(z)^2+v(z)^2$ and then using Cauchy-Riemann equations to simplify.

However in the solutions it was directly given that $ \Delta |f(x+iy)|^2 = 4|′()|^2$. I am not sure how this was given directly as there were no other steps.

Why is this step true?