Why is the order of the n-torsion subgroup equals to $n^2$?

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Let $E$ be an eliptic curve over a finite field $\Bbb F_q$ of order $q$.

Let $m$ be an integer relatively prime to $q$.

Why is $E[n](\overline{\Bbb F}_q)\cong\Bbb Z_n\times\Bbb Z_n$?

It's obvious from Lagrange theorem that it is divisible by $\Bbb Z_n$, but why is the number of left cosets also $n$?