Given:
$f_1 = a$
$f_2 = b$
and
$f_n = \dfrac{5f_{n-1} + 1}{25 \cdot f_{n-2}}$
You can just start doing the algebra to show
$f_3 = \dfrac{5b + 1}{25a}$
$f_4 = \dfrac{5a + 5b + 1}{125ab}$
$f_5 = \dfrac{5a + 1}{25b}$
$f_6 = a$
$f_7 = b$ .....
But why is this happening i.e. what in the definition of the recurrence makes this cyclic and determines the cycle length?