I was reading about group theory in Herstein's book (mentioned below) and I came across a couple of propositions that were not clear to me, in the sense that I couldn't quite figure out why they were true and I would really appreciate if you could help me understand them.
They are the following:
Thus there is a one-to-one correspondence between homomorphic images of G and normal subgroups of G. [...] The set of groups so constructed yields all homomorphic images of G (up to isomorphisms).
Herstein, I. N., Topics in algebra, Lexington, TX: Xerox College Publishing. xi, 388 p. (1975). ZBL1230.00004.
The constructed set mentioned in the quote above is the set $ \left\{G/N: N \triangleleft G \right\} $
I can understand why given a normal subgroup $N$ of $G$, one can associate a homomorphic image of G, namely, $G/N$, but is the converse true, I mean, can I associate a normal subgroup $N$ of $G$ given a homomorphic image of a group $G$? How exactly does the given set yield all homomorphic images of $G$?
Thanks in advance!
The trick between the correspondence lies in the isomorphism theorems. You already know that to every normal subgroup of $G$ there corresponds a unique homomorphic image (upto isomorphism). Now, suppose that $h:G\to H$ is a group homomorphism, then $\ker(h)$ is normal, and by the first isomorphism theorem $$G/\ker(h)\cong h(G).$$