the correct answer is $\begin{pmatrix} -5&3&-6\\-6&3&-7\\-2&1&-2 \end{pmatrix}$
So I think the mistake might be in the first two row operations but I see nothing?
2026-03-29 18:50:32.1774810232
Why is this finding inverse of a matrix by row operation not working?
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Probably because $1-3\cdot(-2)=7$ and not $6$ in the [$r_3=r_3-3r_2$]-step. If you correct that you'll get $\begin{pmatrix} -5&3&-6\\-6&3&-7\\-2&1&-2 \end{pmatrix}$ as the inverse.