Why is this parametrization of a hemisphere wrong?

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I'm learning about surface integral, and one problem uses the surface of a hemisphere with radius $2$. $(x^2+y^2+z^2=4, z \geq 0)$ So I now want to find the parametrization $r(t, s)$. I thought I could do the following; First, look at it from a topdown perspective, then the $x$ and $y$ coordinates will be $2\cos s$ and $2\sin s$ respectively, with $s$ ranging from $0$ to $2\pi$. Then, $z$ will simply be $t$ ranging from $0$ to $2$.

Looking at it again, I think I know what's wrong -- I'm basically constructing a cylinder right now, not a sphere, since my $x-y$ length is always $2$ although it should get smaller when getting higher up. However, how should I best bring $t$ into this?

In general, how can I come up with a parametrization "fast"? During an exam I wouldn't have the time to think about it for too long.

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The simplest parametrization of parts of a sphere uses spherical coordinates:

$$\begin{align}x&=r\sin\theta\cos\varphi,\\ y&=r\sin\theta\sin\varphi,\\ z&=r\cos\theta, \end{align}$$

where $r$ is the radius, $\varphi\in[0,2\pi)$ and $\theta\in[0,\pi]$ for an entire sphere. Here, $\varphi$ describes the "horizontal" rotation (the axis of rotation being the $z$-axis), while $\theta$ is the angle between the $z$-axis and the line connecting the parametrized point to the origin. A hemisphere is obtained by restricting $\theta$ to $[0,\frac{\pi}{2}]$. Here is a vizualization from Wikipedia:

enter image description here

Coming up with this quickly is not something you're supposed to do in an exam. In an exam, you're supposed to already know the most important coordinate systems: polar, spherical and cylindrical coordinates should be at your disposal without having to derive them manually.