why non-orientable surface does not separate its normal bundle

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I was trying to prove that if $S$ is a non-orientable surface embedded in orientable 3-manifold $M$. Then $S$ does not seperate the normal bundle $NS$ and $M$ as well.

It's easy to check that if $S$ is orientable(for example the cylinder in $\Bbb{R}^3$), $S$ may seperate the normal bundle, I have no idea why the seperating property is related to the orientability of the normal bundle ?