Why only projective varieties can be Kahler?

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Say we have a complex variety given by:

$$x^5+y^4+3=0$$

with $(x,y)\in \mathbb{C}^2$. Then apparently this is not a Kähler surface. (Or is it?) But if we do the projective completion:

$$x^5+y^4z+3z^5=0$$

With $(x,y,z)\in \mathbb{PC}^2$ then this is a Kähler surface as all complex projective varieties in complex-projective space are Kähler as "Every smooth complex projective variety" is Kähler.

But the second case is just the first case with extra points `at infinity'.

So how can you have a complex structure on the second case but not on the first? The second is just the first projected onto the hyper-plane $z=1$ with some points projected to points at infinity

The first case is non-compact but this does not seem to be a condition of Kähler surfaces. Why is the first case not called Kähler also?