Consider the function $x\mapsto\min\{\alpha\mid x\in P_\alpha\}$. Since $P$ is a set, its image is a set of ordinals. So there is some $\theta$ which is an upper bound.
Now it is easy to see that $P_\theta=P_{\theta+1}$, since no new members could be added, we have exhausted $P$.
Consider the function $x\mapsto\min\{\alpha\mid x\in P_\alpha\}$. Since $P$ is a set, its image is a set of ordinals. So there is some $\theta$ which is an upper bound.
Now it is easy to see that $P_\theta=P_{\theta+1}$, since no new members could be added, we have exhausted $P$.