Albert and Ben each have several marbles. if Albert gives 6 of his marbles to Ben, they will have the have the same amount of marbles. if Albert gives half of his marbles to Ben, then Ben will have 8 more marbles then Albert will have. how many marbles in total do they have?
The correct answer is 28.
When I solved it, I got 14 marbles for Albert and 8 for Ben which in total is 22 but it wasn't any of the 5 options so I want to know how they got 28.
How I tried solving it: first, I put a random number of marbles that Albert could have. lets say I put 18. then I subtracted 6 from it to get the number of marbles Ben could have as it says in the first statement $(18-6=12).$ After that, I divided the amount of marbles Albert has by 2 $(18/2=9).$ Then I added 9 to 12 to get the amount of marbles Ben could have. Then I subtracted 9 from 18 and I got 9. If that subtracted from 12 would give a number less then 8, I would lower the amount of marbles Albert could have in the beginning and start over. If it was higher then 8, I would up the amount Albert could have in the beginning and start over. I would do this until it matched the 2 statements in the question.
Let Albert have $A$ marbles and Ben have $B$ marbles. The two statements can then be written as \begin{eqnarray*} A-6=B+6 \\ \frac{A}{2} + 8 = \frac{A}{2} +B. \end{eqnarray*} Should be easy from here ?