the question is to turn this question {1/4} double root to standard form.
What i got is x = 1/4, x= 1/4 once you multiply them you get x^2 -1/2x -1/16 I think not sure if I'm correct
and thanks to who ever it is that edits my question...i don't know how to write it in a proper way and am learning but thanks
You are correct. For any two roots $a$ and $b$, the quadratic with those roots is $0 =(x-a)(x-b) =x^2-(a+b)x + ab $.
If $a = b = \frac14$, the quadratic is $x^2-(\frac14+\frac14)x+\frac14\cdot \frac14 =x^2-\frac12x+\frac1{16} $.