Write down two values of $k$ for which the equation $f(x)=k$ has exactly two solutions.

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$f(x)=5\sin(x+0.927)$

It was also written in another form as $3\sin x+4\cos x$.

I understand that for $k$ to have no solutions, the range would be $|k|>5$. But this question confused me, because it asked for specific values rather than a range, and I assume it asks for two solutions for EACH answer of $k$.

Thanks in advance!